If you realize that a 4 digit palindrome is basically a two digit number followed by it's own reverse, you can re-phrase this question as 'how many two digit numbers are there?' Which would then mean that (if you're considering zeros as digits without a non-zero leading term) there would be a 4 digit palindrome 0000 for the two digit 00; a four digit 0110 for the two digit 01; 0220, 02; etc etc. So the number of four digit palindromes would be the same as the quantity of whole numbers from 00 to 99. So I believe the total answer to your question would be 100.
7
8100
four
250 of them.
500
There is 90 four digit palindromes.
There are no four-digit perfect squares that are palindromes.
7000 - 999 ie 6001 four digit numbers
There are 90 four-digit palindromes
90
There are four of them
2240
Four
64
9,000
5*5*4*4 = 400
There are 9 x 10 x 10 x 10, or 9000 four-digit number that can be formed if the leading digit cannot be zero.