Your question leaves a lot to the imagination. One can only assume that you are talking about an object in circular motion, and you wish to know how doubling the radius of the orbit will change the linear -- or tangential -- speed of the object. The trouble is, we don't know the angular velocity of either condition, so let's assume there is no difference. The following model illustrates. Imagine you have a rope two meters long with a handle on one end, a ball on the other, and another ball located directly in between. Now, imagine yourself swinging the rope overhead so that the balls trace a circular path. Both balls will have the same angular velocity, but the outside ball is moving much faster, because it has a greater distance to cover. How much greater? Well, since the circumference of a circle is proportional to the square of the radius, doubling the radius quadruples the circumference, so the outside ball must travel four times faster to keep up with the inside ball.
the tangential velocity is equal to the angular velocity multiplied by the radius the tangential velocity is equal to the angular velocity multiplied by the radius
2.09
Use the formula for centripetal acceleration: velocity squared / radius.
The radius multiplied by 2 => 2r
double the radius or multiply by 2 the radius
the tangential velocity is equal to the angular velocity multiplied by the radius the tangential velocity is equal to the angular velocity multiplied by the radius
Vt=w*r where; * is multiply Vt is tangential velocity w is omega(angular mometum) r is radius
The tangential velocity is greater as the radius of the point on the rotating object increases. For a rotating object v = rw Where v is the tangential velocity r is the radius of the point And "w" is omega or angular velocity (in radians per second)
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Since a=Rω², when you double the radius, but hold the angular velocity constant, you double the force. Also when you increase the angular velocity or velocity by a factor of √2 and hold the radius constant.
-- tangential speed -- angular velocity -- kinetic energy -- magnitude of momentum -- radius of the circle -- centripetal acceleration
Angular velocity just means how fast it's rotating. If youaa want more angular velocity, just rotate it faster or decrease the radius (move it closer to the center of rotation). Just like force = rate of change of momentum, you have torque= rate of change of angular moment Or We can increase the angular velocity of a rotating particle by applying a tangential force(i.e. accelaration) on the particle. Since the velocity of the particle is tangential with the circle along which it is moving, the tangential accelaration will not change the diriction of the velocity(as angle is 0),but will cause a change in magnitude. Thus angular velocity will increase.
Not enough information. If the ball moves in a circle, you would also need the radius of the circle, and the mass of the ball.In this case, you can: 1) Calculate the corresponding centripetal acceleration, by using Newton's Second Law (a = F/m). 2) Calculate the tangential speed, using the formula for centripetal acceleration: acceleration = velocity squared / radius.
velocity of any satellite revolving around any planet is 0 with reference to cos theta. the velocity in circular motion is taken in tangential direction. when the velocity of any satellite is taken tangential , then it forms 90 degrees with the radius of the Earth. we know that cos90 = 0. therefore,velocity of satellites is 0 with reference to cos theta. but this contradicts the fact that " any body with 0 velocity would collide the Earth" stated by Issac Newton. scientists are still researching to get an appropriate answer to this question. - by d.s.rahul
speed v = rotational velocity w x radius r; w = 2 x pi /2 = pi; v = 31.4 m/sec
The time, T , it takes for an object to go thru one comblete rotation of 360 degrees or 2pi radians is its "period." The rate at which it completes the rotation is its "angular velocity." The rate is the angle (in radians) divided by the time. So , Angular Velocity = 2 pi / T.
in my opinion, the velocity of any body moving in a circular path is directed in tangential direction. when the velocity is took tangential,its angle formed with reference to the earths radius is 90 degrees. we know that cos90 = 0. therefore,the velocity of the satellites revolving around the earth must be 0 with reference to cos theta. velocity of any satellite revolving around any planet is 0 with reference to cos theta. but this contradicts the fact that " any body with 0 velocity would collide the Earth" stated by Issac Newton. scientists are still researching to get an appropriate answer to this question. - by d.s.rahul