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You are correct my friend! Surface Area of a Sphere is indeed = 4(pi)r^2 and that is also equal to Circumference times Diameter!
It will be the surface area of a sphere but it depends on the distance from the center to a certain point, also known as the radius.
Surface area, S.A., of a sphere with radius r equals to 4pir2.Since the diameter is decreased by 25%, the radius is also decreased by 25%.That is r - 0.25r = 0.75r.So that S.A. = 4pi(0.75r)2 = 2.25pir2
The surface area of a semicircle has the round surface which is half a sphere and also has the flat surface which is a circle.
4 * pi * radius * radius or (pi * diameter * diameter) / 3 Also ( 4 * 3.14 * radius squared ) Also ( 88/7 * radius squared )
A radius of a sphere is the distance from its centre to its surface. It is also half of the diameter. If you know the circumference of a circle, you can calculate its radius. Circumference divided by Pi divided by 2 = radius.
You are correct my friend! Surface Area of a Sphere is indeed = 4(pi)r^2 and that is also equal to Circumference times Diameter!
It will be the surface area of a sphere but it depends on the distance from the center to a certain point, also known as the radius.
It will be the surface area of a sphere but it depends on the distance from the center to a certain point, also known as the radius.
Surface area, S.A., of a sphere with radius r equals to 4pir2.Since the diameter is decreased by 25%, the radius is also decreased by 25%.That is r - 0.25r = 0.75r.So that S.A. = 4pi(0.75r)2 = 2.25pir2
The volume of a sphere with a radius of 12 units is: 7,238 units3The answer above is correct but the answer ALSO can be 2304 units3
The surface area of a semicircle has the round surface which is half a sphere and also has the flat surface which is a circle.
The centre of a sphere does not provide enough information. You also need its diameter or radius.
4 * pi * radius * radius or (pi * diameter * diameter) / 3 Also ( 4 * 3.14 * radius squared ) Also ( 88/7 * radius squared )
If the radius is larger, the surface will also be larger. As a functional dependency, you only need one - the radius, or the surface - whatever.
Suppose the radius of the sphere is R. The base of the cone is the same as the base of the hemisphere so the radius of the base of the cone is also R. The apex of the cone is on the surface of the hemisphere above the centre of the base. That is, it is at the "North pole" position. So the height of the cone is also the radius of the sphere = R. So the ratio is 1.
When cells get smaller, the volume (as well as mass) decreases faster than the surface area so the surface:volume increases. Cells with a high surface:volume are more effective in receiving nutrients through diffusion. A cell (assume perfect sphere) with radius 2 has a surface area of 16pi and volume of 32pi/3. A cell with radius 3 has a surface area of 36pi and volume of 108pi/3. Also relatively speaking, volume can be thought of as y=x3 and surface area as y=x2. When there is a change in x, the change is more dramatic in the volume, so small cells have high ratios and large cells have low ratios.