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Cow = x Chicken =y

x+y=34 -> x=34-y

4x+2y=100

4(34-y)+2y=100

126-4y+2y=100

-2y=-26

y=13 (13 chickens)

x=34-13=21 (21 cows)

There are 21 cows and 13 chickens.

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Q: If you have 34 chickens and cows and count 100 legs how many do you have each of chickens and cows?
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