12' x 10'
156.2 units.
Let x be the unknown dimension x+x+x+20+x+20 = perimeter of the rectangle 4x+40 = 160 4x = 160-40 4x = 120 x = 30 Therefore the width is 30 cm and the length is 50 cm
What does the 120 feet refer to?
Assuming you mean a "rectangle", it would be 100*2+120*2 = 440ft.
Very hard question, It took me one hour to solve it. I think it is 0.12 m or 120 mm.
Let x be the unknown dimension x+x+x+20+x+20 = perimeter of the rectangle 4x+40 = 160 4x = 160-40 4x = 120 x = 30 Therefore the width is 30 cm and the length is 50 cm
156.2 units.
What does the 120 feet refer to?
It is: 120+80+120+80 = 400 feet
700cm
== == 2(L + B) = 44, so L + B = 22; also LB = 120. So we come up with L(22 - L) = 120, leading to L = 12 and B = 10.
To answer this simply try a few out for yourself. In a 2x1 cm rectangle, the area is 2 cm squared and the perimeter is 6 cm In a 12x10 rectangle, the area is 120 cm squared and the perimeter is 44 cm. In some cases, the perimeter is larger and in others it is smaller. To answer your question, no, the perimeter of a rectangle is NOT always greater than its area.
P = 46 cm A = 120 sq cm
Assuming you mean a "rectangle", it would be 100*2+120*2 = 440ft.
Very hard question, It took me one hour to solve it. I think it is 0.12 m or 120 mm.
To find the width of a rectangle, multiply the lenght by 2 and subtract it from the perimeter. Once this is done you are left with the two width sides of the rectangle. To find the width divide this number by 2 and you have your answer. For exaple: P= 120 cm L= 40 cm L* 2 = 80 120 - 80 = 40 40/2 = 20 W=20
In this problem, you're essentially trying to find the perimeter of this rectangle with sides of 80 and 120. To find the perimeter, simply add these two lengths together, then multiply that answer by two. This works in a rectangle because there are always two sets of identical sides so doubling each one is an easy step.