Of the 36 possible combinations rolling two dice there are 2 combinations that add up to 11 so the odds are 18:1
It is 1/18.
The probability is 7/36.
uummm!!!! The probability would maybe close to 5 or 4. * * * * * The answer is clearly incorrect because the probability of an event cannot be greater than 1. The actual probability, assuming the dice are fair, is 4/36 = 1/9 = 11.11...%
With standard dice, zero.
It is 5/11.
It is 1/18.
The probability is 7/36.
uummm!!!! The probability would maybe close to 5 or 4. * * * * * The answer is clearly incorrect because the probability of an event cannot be greater than 1. The actual probability, assuming the dice are fair, is 4/36 = 1/9 = 11.11...%
The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.
If they are normal dice, the probability is 0.
try it and see!
The probability of the event is 25/36.
With standard dice, zero.
If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032
You must notice that it is easier to find the probability that none of the dice are six. This is the complement of the answer. Pc= (55)/(65) = .4019 *the first die has 5 ways to not equal six, and so on for the remaining dice. [55] outcomes have no six. *the total number of outcomes gives each die 6 ways to fall. [65] outcomes overall. *Probability is the favorable outcome divided by the total number of outcomes. *Probability of an event is 1 minus the complement of the event. P = 1 - .4019 P = .5981 <<<<<<FINAL ANSWER
It is 5/11.
Independent. The chance the die are either a total of 11 or one will be a 4 are not related. --------------------------------------------------------------------------------------------- There are only two ways the sum of the resulting numbers of two dice thrown give 11: (5,6) and (6,5). The probability for event A is: P(A) = 2(1/6)(1/6) = 1/18 = 0.05555... ≈ 5.56% Given event A, there is no possibility that one of the two dice show a 4. The conditional probability is, P(B|A) = 0. So, event B is dependent of event A.