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Assuming the uniform continuous distribution, the answer is 29/49. With the uniform discrete distribution, the answer is 29/50.
Assuming a constant wavelength, then increasing the wave speed will increase the frequency.
Assuming that seconds refers to the period, the frequency is the reciprocal (1 / period in seconds). The height of the wave is irrelevant in this case.
A reflex angle. Assuming the angle is also less than 360 degrees.
Assuming you mean sheets measuring 4 feet x 8 feet... Six sheets exactly.
Assuming the uniform continuous distribution, the answer is 29/49. With the uniform discrete distribution, the answer is 29/50.
Assuming that "past continuous" means the same thing as "past progressive", the answer is "was thinking".
Frequency drops, assuming the velocity stays the same.
Assuming you mean the lowest frequency humans can hear, that's about 20 Hz.
Assuming a constant wavelength, then increasing the wave speed will increase the frequency.
it is directly proportional to frequency so if frequency increases wavelength also increases
The period and frequency of a wave are inversely related, i.e. the period is the time it takes for wave to go through a cycle, and the frequency is the number of cycles in a certain time period. For example, a wave with a period of 0.5 seconds would have a frequency of 2 per second. Since these properties are the inverse of each other, than they will be opposite when changing. If the period decreases (i.e. gets shorter, faster) than the frequency increases. Or vice versa.
10
Assuming that we have a Normal Distribution of Data, approx. 65% of the data will fall within One Sigma.
Assuming you mean visible light, that would be red light.
Frequency=velocity of light/wavelength We know that the velocity of light is 3x10^8m/s From your wavelength, I am assuming that the number is in meters Thus the frequency =(3x10^8)/(6.14x10^-7) frequency = 4.8859x10^14 Hz
The frequency of a sound wave is the characteristic of the wave that gives rise to the sensation of pitch, assuming that the wave is not so complex that it is perceived as white noise.