The odds of each coin toss are 50-50. The coin has no memory; there is no record of what the last four tosses are. EVERY toss is at 50-50 odds.
The chance is 50%-50% that it will be heads or tails; this does not change regardless of the number of previous tosses and their results.
Pr(H at least once in 10 tosses) = 1 - pr(No H in 10 tosses) = 1 - Pr(10 T in 10 tosses) = 1 - (1/2)10 = 1 - 1/1024 = 1023/1024
Prob(Head in 300 tosses of a coin) = 1 - Prob(not a single H in 300 tosses) = 1 - (1/2)300 = 1 - (4.91*10-91) = 0.999...9998 where there are 90 9s before the 8.
The probability is 0.09766%.Each toss has a ½ chance to be heads. To combine probabilities use multiply them. So the probability to get two heads out of two tosses is ½ * ½, and three heads out of three tosses is ½ * ½ * ½. So the exact answer is 0.5^10
With 5 coin tosses there are 32 possible outcomes. 10 of these have exactly 2 heads, and 26 of these have 2 or more heads.For exactly two coins are heads: 10/32 = 31.25%For two or more heads: 26/32 = 81.25%
0.53 = 0.125.
The probability of getting five heads out of 10 tosses is the same as the probablity of getting five tales out of ten tosses. One. It will happen. When this happens, you will get zero information. In other words, this is the expected result.
A coin is tossed until ahead appears. What is the expectation of the number of tosses required?
It means that if the coin were tossed an infinite number of times, half of the tosses would come up heads and half would be tails.
The adjective forms for the verb to 'toss' are the present participle, tossing (The tossing sessions have strengthened my wrist.), and the past participle, tossed(The tossed confetti and streamers were cleaned up by maintenance before dawn.).
The chance is 50%-50% that it will be heads or tails; this does not change regardless of the number of previous tosses and their results.
Usually, it takes 2-5 flips until a head appears.
It is 1/8.
Pr(H at least once in 10 tosses) = 1 - pr(No H in 10 tosses) = 1 - Pr(10 T in 10 tosses) = 1 - (1/2)10 = 1 - 1/1024 = 1023/1024
2 sides x 10 tosses, so your possibilities is 2^10 or 2x2x2x2x2x2x2x2x2x2 =1024 outcomes.
The probability of getting two tails in the first two is 1/4. And it does not matter how many more times the coins are tossed after the first two tosses.
Prob(Head in 300 tosses of a coin) = 1 - Prob(not a single H in 300 tosses) = 1 - (1/2)300 = 1 - (4.91*10-91) = 0.999...9998 where there are 90 9s before the 8.