The sextant reads 5 minutes too high
I will assume that you mean to ask, "What is the arc length of curve C from t=0 to t=1 if curve C is defined parametrically by x=1+2e^t and y=e^t?" I can answer this question. dx/dt=2e^t and dy/dt=e^t. Arc length = a∫b √[(dx/dt)2+(dy/dt)^2] = 0∫1 √[4e^(2t)+e^(2t)]dt = 0∫1 √[5e^(2t)]dt. = 0∫1 [(√5)(e^t)]dt = √5 x (e^1-e^0) = √5 x (e-1) = e√5-√5. Difficult? Maybe. Fun? Hopefully. Accurate? Definitely!
template<class T> void insertion_sort(T A[], size_t size) { if( size<2 ) return; for( size_t index=1; index<size; ++index) { T value = A[index]; size_t gap = index; size_t left = index-1; while( gap!=0 && value<A[left] ) A[gap--]=A[left--]; A[gap]=value; } }
The formula to calculate error in data can vary depending on the context, but a common one is the Absolute Error, which is calculated as the absolute difference between the measured value (M) and the true value (T): [ \text{Absolute Error} = |M - T| ] For relative error, you can use: [ \text{Relative Error} = \frac{|M - T|}{|T|} \times 100% ] This gives you a percentage that indicates how significant the error is in relation to the true value.
The ratio of arc time to total time is calculated by dividing the duration of the arc time by the overall duration of the total time. If the arc time is represented as ( A ) and the total time as ( T ), the ratio can be expressed as ( \frac{A}{T} ). This ratio indicates the proportion of time spent in the specified arc compared to the entire duration. To express it as a percentage, you can multiply the ratio by 100.
#include<iostream> #include<iomanip> #include<time.h> template<typename T> size_t find(T& data, T a[], size_t size) { size_t index=0; do { if(a[index]==data) break; } while(++index<size); return(index); } template<typename T> void print(T a[], size_t size) { using std::cout; using std::endl; using std::setw; size_t index=0; do{ if(index&&index%20==0) cout<<endl; cout<<setw(3)<<a[index]; }while(++index<size); cout<<endl; } int main() { srand((unsigned)time(NULL)); const size_t size=100; unsigned int a[size]; size_t index=0; do{ unsigned int data=rand()%100; do{ data=rand()%100; } while(find(data,a,index)<index); a[index]=data; } while(++index<size); print(a,size); }
James T. Stewart has written: 'Rehab index'
static error coefficients are the error calculated when steady state is reached. so, the dynamic error coefficients give the error calculated with time. it just calculated by taking the inverse Laplace transform of E(s) term resulting in the equation: e(t)=k0 r(t) + k1 r('t) + k2 r''(t) + ... where, k0: position error coefficient k1: velocity error coefficient k2: acceleration error coefficient sks..
If the true value is t and the calculated or measured value is v then absolute error = |v - t|, the absolute value of (v - t).If v >= t then the absolute value is v - tif v
trilobites
I. T. E. Firkins has written: 'Index to plays 1800-1926'
If -t = 5, then t = -5
Judith T. Lessler has written: 'Nonsampling error in surveys' -- subject(s): Error analysis (Mathematics), Surveys