Interior angles of n-sided polygon total (2n - 4) right angles, in this case 16 x 90 degrees, so each angle is 16 x 90/10 ie 144 degrees. Exterior angle is 180 - 144 ie 36 degrees.
1980 interior angles and 360 exterior angles
Exterior angles: 360 Interior angles: 1440
Exterior angles: 360 degrees Interior angles: 1080 degrees
Exterior angles = 360 degrees Interior angles = 1800 degrees
Exterior angles . . . 360 degrees Interior angles . . . 1,080 degrees Total . . . . . . . . . . . 1,440 degrees
The sum of what of a 92 sided polygon? The lengths of the sides? The exterior angles? The interior angles?
1980 interior angles and 360 exterior angles
Exterior angles: 360 Interior angles: 1440
Exterior angles: 360 degrees Interior angles: 1080 degrees
Exterior angles = 360 degrees Interior angles = 1800 degrees
Exterior angles: 360 degrees Interior angles: 3,960 degrees
Remember the two equations. Exterior angle = 360 / no. of sides. Interior angle = 180 - exterior angle. So for 102 sided polygon. exterior angle = 360/102 = 3.5294... Interior angle = 180 - 3.5294... = 176.4706.... Hence sum of the 102 sided polygon's angles is 102 X 176.4706 = 18,000 degrees. ( to nearest degree).
Exterior angles: 360 degrees Interior angles: 3,600 degrees
An 8 sided polygon is an octagon and has exterior angles that add up to 360 degrees and its interior angles add up to 1080 degrees
Sum of exterior angles of any sided polygon is 360 so sum of exterior angle of 6 sided polygon (hexagon) is 360
Interior angles using the formula: (24-2)*180 = 3960 degrees Exterior angles: 360 degrees
Sum of exterior angles = 360 degrees Sum of interior angles = 1440 degrees