Remember the two equations.
Exterior angle = 360 / no. of sides.
Interior angle = 180 - exterior angle.
So for 102 sided polygon.
exterior angle = 360/102 = 3.5294...
Interior angle = 180 - 3.5294... = 176.4706....
Hence sum of the 102 sided polygon's angles is
102 X 176.4706 = 18,000 degrees. ( to nearest degree).
The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.
the sum of the interior angles of a 35-gon.
The sum of the measures of the interior angles of a heptagon is 900 degrees.
A polygon that has a sum of 2520 degrees of interior angles has 16 sides
Sum of exterior angles: 360 degrees Sum of interior angles: 2160
The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.
The sum of the interior angles is 360.
No, the interior angles of a triangle sum to 180o The interior angles of a quadrilateral sum to 360o.
Exterior angles add up to 360 degrees Interior angles add up 18000 degrees
The sum of the interior angles of a parallelogram is 360 degrees.
Interior angles of a triangle have a sum of 180 degrees.
A square always has a sum of 360 degrees for the interior angles.
A rhombus is a quadrilateral, so the sum of its interior angles is 360o.
The sum of the four interior angles of a trapezoid is 360 degrees.
(number of sides-2)*180 = sum of the interior angles
Do you mean the sum of interior angles? If so then it's: (number of sides -2)*180 = sum of interior angles
The interior angles sum to 180*(N - 2) degrees.The interior angles sum to 180*(N - 2) degrees.The interior angles sum to 180*(N - 2) degrees.The interior angles sum to 180*(N - 2) degrees.