Remember the two equations.
Exterior angle = 360 / no. of sides.
Interior angle = 180 - exterior angle.
So for 102 sided polygon.
exterior angle = 360/102 = 3.5294...
Interior angle = 180 - 3.5294... = 176.4706....
Hence sum of the 102 sided polygon's angles is
102 X 176.4706 = 18,000 degrees. ( to nearest degree).
The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.
the sum of the interior angles of a 35-gon.
A polygon that has a sum of 2520 degrees of interior angles has 16 sides
The sum of the measures of the interior angles of a heptagon is 900 degrees.
Sum of exterior angles: 360 degrees Sum of interior angles: 2160
The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.
No, the interior angles of a triangle sum to 180o The interior angles of a quadrilateral sum to 360o.
The sum of the interior angles is 360.
Exterior angles add up to 360 degrees Interior angles add up 18000 degrees
The sum of the interior angles of a parallelogram is 360 degrees.
Interior angles of a triangle have a sum of 180 degrees.
(number of sides-2)*180 = sum of the interior angles
The sum of the four interior angles of a trapezoid is 360 degrees.
A square always has a sum of 360 degrees for the interior angles.
A rhombus is a quadrilateral, so the sum of its interior angles is 360o.
Do you mean the sum of interior angles? If so then it's: (number of sides -2)*180 = sum of interior angles
The interior angles sum to 180*(N - 2) degrees.The interior angles sum to 180*(N - 2) degrees.The interior angles sum to 180*(N - 2) degrees.The interior angles sum to 180*(N - 2) degrees.