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angle a= 87.3819 DEG. (approx.)

angle b= 62.6181 DEG. (approx.)

angle c= 30 deg.

side opposite angle a= 9 cm (given)

side opposite angle b= 8 cm (given)

side opposite angle c= 4.5047 cm

this triangle is almost a 30, 60, 90 better known as a special right triangle where the side opposite the right angle is twice the size of the side opposite the 30 deg. angle so the side opposite angle b would be: 9/2 times the square root of 3.

to solve this problem (since this triangle is not really a right triangle) you must use the law of cosines coupled with the law of sines in order to solve this problem.

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Q: Interior angle is 30 degrees between two sides that are 9 centimeters and 8 centimeters What is the other two angles and the perimeter of the triangle?
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