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is there some way of calculating f(5) where f(0) equals 1 and f(n) = n!! . . (f(n-1) factorial signs)?

Updated: 10/22/2021

I actually aldready calculated f(4) with perl hypercalc and it is approximately equal to 10^10^10^ . . (539 10's) ^10^10^10^25

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gamerarcioko

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Q: Is there some way of calculating f(5) where f(0) equals 1 and f(n) = n!! . . (f(n-1) factorial signs)?
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