no
If those are the only values, no.
The relation ship betwee them that Un+Un+1=5
The first number in each pair must be unique.
The right part of the relation needs to be unique - no numbers may be repeated. It's clear that in this case, you would need to remove more than one pair.
1 it is the difference between the highest and lowest number
The range is {-3, 2, 0}.
A huge number. 0 + 1 + 2 = 3 0 + 2 + 1 = 3 1 + 0 + 2 = 3 1 + 2 + 0 = 3 2 + 0 + 1 = 3 2 + 1 + 0 = 3 -0 + 1 + 2 = 3 -0 + 2 + 1 = 3 1 - 0 + 2 = 31 + 2 - 0 = 32 - 0 + 1 = 32 + 1 - 0 = 3 0 - 1 + 3 = 2 0 + 3 - 1 = 2 -1 + 0 + 3 = 2 -1 + 3 + 0 = 2 3 + 0 - 1 = 2 3 - 1 + 0 = 2 -0 - 1 + 3 = 2-0 + 3 - 1 = 2-1 - 0 + 3 = 2-1 + 3 - 0 = 23 - 0 - 1 = 23 - 1 - 0 = 2 0 - 2 + 3 = 1 0 + 3 - 2 = 1 -2 + 0 + 3 = 1 -2 + 3 + 0 = 1 3 + 0 - 2 = 1 3 - 2 + 0 = 1 -0 - 2 + 3 = 1-0 + 3 - 2 = 1-2 - 0 + 3 = 1-2 + 3 - 0 = 13 - 0 - 2 = 13 - 2 - 0 = 1 1 + 2 - 3 = 0 1 - 3 + 2 = 0 2 + 1 - 3 = 0 2 - 3 + 1 = 0 -3 + 1 + 2 = 0 -3 + 2 + 1 = 0 For each of these equations there is a counterpart in which all signs have been switched. For example 0 + 1 + 2 = 3 gives -0 - 1 - 2 = -3and so on. Now, all of the above equations has three numbers on the left and one on the right. Each can be converted to others with two numbers on each side. For example:the equation 0 + 1 + 2 = 3 gives rise to0 + 1 = 3 - 20 + 1 = -2 + 30 + 2 = 3 - 10 + 2 = -1 + 31 + 2 = 3 - 01 + 2 = -0 + 3-0 + 1 = 3 - 2-0 + 1 = -2 + 3-0 + 2 = 3 - 1-0 + 2 = -1 + 31 + 2 = 3 + 01 + 2 = +0 + 3 As you can see, the number of equations is huge!
A relation is any set of ordered pairs (x, y), such as {(2, 5), (4, 9), (-3, 7), (2, 0)} or {(2, 3), (5, -2)}. A function is a special type of relation in which each x-value is assigned a unique y-value. So in the two examples given above, the first relation is NOT a function because the x-value of 2 is assigned two different y-values: 5 and 0. The second example above is a relation, since each x-value given (i.e., 2 and 5) is only assigned to one y-value (i.e., 3 and -2, respectively). Two additional examples: {(0, 5), (1, 3), (1, 8), (4, -2)} is NOT a function, because the x-value of 1 is assigned to two different y-values. {(0, 3), (1, 4), (3, -2), (4, 7), (5, 0)} is a function, because there is no x-value that is assigned to more than one y-value. When graphed in the Cartesian plane, you can determine if a relation is a function or not by the "vertical line test", which says that if there is any place where a vertical line can be drawn that will pass through the graph more than once, then that relation is NOT a function. But if every vertical line that can possibly be drawn only passes through the relation at most once, then that relation is a function.
1 1/2
E|----------------|-------0-1-0----|----------------|--------1-0-----|--| B|--0-1-----0-1--|--0-1--------1-|------0-1-------|------1----1---|--| G|0-------0------|0--------------2|0-------------0-|-----2-------2-|0-| D|----------------|-----------------|----------------|3--3------------|--| A|----------------|-----------------|----------------|-----------------|--| E|----------------|-----------------|----------------|-----------------|--| E|----3-1---------|-----------------0-|1---------------| B|--------1-------|-----------3-1-----|----------------| G|----------0-----|0-------0----------|----------------| D|------------2-3|----2-3------------|----------------| A|----------------|--------------------|----------------| E|----------------|--------------------|----------------| E|----------------|--------0-1-0----|----------------|-------1-0-----|--| B|--0-1-----0-1-|---0-1-------1--|------0-1-------|------1----1---|--| G|0-------0------|-0--------------2|0------------0-|-----2-------2-|0-| D|----------------|------------------|----------------|3--3-----------|--| A|----------------|------------------|----------------|----------------|--| E|----------------|------------------|----------------|----------------|--|
the four sets of quantum numbers are: 2, 0, 0, +1/2 2, 0, 0, -1/2 1, 0, 0, +1/2 1, 0, 0, -1/2