Yes if you mean (1, 3) and 3y = 2x+1
2x plus 3y
3(2x + 3y)(2x - 3y)
2x + 5y = 16 -2x - 3y = -14 2y = 2 y = 1 / x = 5.5 (5.5,1) or (5 1/2,1)
2x + 3y = 1 y = 1/3 - 2x/3
-2x+3y=1 3y=1+2x y=(1+2x)/3 Then proceed to find points by plugging in given or arbitrary values of x.
-2x plus 3y equals 1
If you mean: 6x-3y = -33 and 2x+y = -1 Then solving the simultaneous equations by substitution: x = -3 and y = 5
2x/3y
No, to check if the values are a solution, substitute x=1 and y=3 into the equation and see if it holds true. In this case, when x=1 and y=3, the equation becomes 3(3) ≠ 2(1) + 1, which simplifies to 9 ≠ 3. So, 1,3 is not a solution to the equation 3y = 2x + 1.
If you mean 2x -3y = 6 then it is true and so is (3, 0)
2x - 3y = 6 2x = 6 + 3y 2x - 6 = 3y : 3y = 2x - 6 y = 2/3x - 2
1) 2x + 1 = 3y 2) 4 = 3y - 10 this can be re-written as 3y = 4 + 10 Therefore 2x + 1 = 4 + 10 2x = 13 x = 6.5 Sustitute x = 6.5 in equation 1) above 2x + 1 = 3y 2 (6.5) + 1 = 3y therefore 3y = 13 +1 3y = 14 y = 14/3 Now substitute y = 14/3 in equation 2) above and watch what happens! 4 = 3(14/3) -10 4 = 4 Therefore the answer is correct!