The mathematical symbols did not appear so I am assuming that your question is if the point (-1,-1) is a solution of y = 3x + 2, in that case, substitute -1 for y and -1 for x and you get
-1 = 3(-1) + 2 or
-1 = -3 + 2 or
-1 = -1
Thus if I assumed the question correctly, then -1,-1 is a solution to y = 3x + 2
x+1=x+2 x=1+2+x 0x=1+2 0x=3 0x=/=3 (=/= means does not equal) so there is no solution
first we assume this to be true. x+1=x+2 x=x+1 x-x=1 0=1 this is not true, so the initial premise that this problem has a solution must be false. There is no solution.
2
The solution is: x = 1 and y = -1
y = x + 1
The solution to the equation 2x plus 2 is 2(x + 1).
The answer would be no solution. x+1=x+2. Subtract 1 from both sides x=x+1. Subtract x from both sides. 1 does not = 0
There is no solution since the equation is inconsistent.
x=-2
No, it is not.
It is (-1, 3).
x2 + x + 1 = 0 ∴ x2 + x + 1/4 = -3/4 ∴ (x + 1/2)2 = -3/4 ∴ x + 1/2 = ± √(-3/4) ∴ x = - 1/2 ± (i√3) / 2 ∴ x = (-1 ± i√3) / 2