No.
If a number is divisible by three, the sum of its digits will be divisible by three. Obviously, the sum of the digits of 10000 is 1, and 1 is not divisible by 3, so 10000 is not divisible by 3.
It is 83667.
10000/3 is 3333.3recurring, so no, it is not divisible by 3
Counting 10000, there are 17999.
10,000 is composite. It is divisible by 2.
Int(10000/3) = Int(3333.3) = 3333
To find how many positive integers less than or equal to 10,000 are divisible by 2, 5, or 10, we can use the principle of inclusion-exclusion. The count of integers divisible by each is: Divisible by 2: ( \frac{10000}{2} = 5000 ) Divisible by 5: ( \frac{10000}{5} = 2000 ) Divisible by 10: ( \frac{10000}{10} = 1000 ) Applying inclusion-exclusion, we have: [ 5000 + 2000 - 1000 = 6000 ] Thus, there are 6000 positive integers less than or equal to 10,000 that are divisible by 2, 5, or 10.
There are 20 palindromes between 10,000 and 99,999 that are divisible by 25.
To find the numbers less than 10,000 that are divisible by 21, 35, and 63, we need to find the least common multiple (LCM) of these three numbers, which is 441. Then, we divide 10,000 by 441 to find how many multiples of 441 are less than 10,000, which is approximately 22. So, there are 22 numbers less than 10,000 that are divisible by 21, 35, and 63.
There are 20 palindromes between 10,000 and 99,999 that are divisible by 25.
Factors of 15 are 1, 3, 5 and 15. Starting with the greatest number, 15 is not divisible by 130. Then, 5 is both divisible by 130 and 10000. So the answer is 5.
10000 = 16 x 625
There are 3598 numbers between 10000 and 99999 which are divisible by 25. They are elements of the set of numbers of the form 25*k, where k is an integer between 41 and 3999 (inclusive).