Yes. By 2, for example.
There are (500-100)/2 = 200 numbers divisible by 2 between 100 and 500 counting 100 but not 500. Of these (500-100)/8 = 50 are divisible by 8. So there are 150 numbers between 100 and 500 divisible by two but not by 8. By relative primeness exactly 50 out of these 150 are divisible by 3 and therefore these 50 are exactly the ones divisible by 6 but not by 8.
126
150
All of them but I assume you mean evenly divisible. 150. 150/2 is 75 150/3 is 50 and 150/10 is 15
There are seven of them. They are: 20, 40, 60, 80, 100, 120 and 140.
150
no.. take an example.. 150 is divided by both 75 and 3..but not by 225..
102, 108, 114, 120, 126, 132, 138, 144, and 150
It is 120, 150, and 180.
150 is divisible by 6 evenly and is divisible by 9 but not evenly
There are eight pairs of numbers divisible by three that sum to 150, and 75 is also divisible by three, so: sum = 17 * 75 = 750 + 525 = 1275
150%% rate:= 150/100 * 100%= 1.5 * 100%= 150%