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No. 127 is not evenly divisible by nine.

127 is evenly divisible by '1' and '127'.

127, 254, 381 and so on.

127

No

No.

No. 127 is not a composite number because it is only divisible by 1 and 127

Only by one and itself. (127 is a prime number).

117 and 225, yes. The rest, no.

The prime factors of 508 are 2, 2, and 127, so 508 is only divisible by 1, 2, 4, 127, 254, and 508.

1, 3, 7, 9, 21, 63, 127, 381, 889, 1143, 2667, 8001.

It is divisible by 3 because 381/3 = 127

No127/9 = 14.111111...

Yes. Its quotient is 127

Yes. The quotient is 127.

NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)

Yes. The quotient is 127.

Yes. It goes in 127 times.

All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.

81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.

No - any number divisible by 9 will have the sum of its digits divisible by 9.

(508) = 2 * (254) (254) = 2 * 127 so, prime factors are 2,2 and 127 so, numbers it will divide by are 2 and 127

Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.

9 is divisible by both 3 and 9

No, 998876 is not divisible by 9.