381 is divisible 3 and only 3
Yes. The quotient is 127.
Some examples are... 381 474 726
yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!
Well, let's take a moment to look at this question. To see if a number is divisible by 3, you can add up the digits and see if that sum is divisible by 3. For 780, 7 + 8 + 0 = 15, which is divisible by 3. But for 320, 3 + 2 + 0 = 5, which is not divisible by 3. So, 780 is divisible by 3. Now, to check if a number is divisible by 5, you can see if the last digit is 0 or 5. In this case, 780 ends in 0, so it's divisible by 5. However, 320 does not end in 0 or 5, so it's not divisible by 5. So, 780 is divisible by both 3 and 5, while 320 is only divisible by 5.
381 is divisible 3 and only 3
No.
Yes. Its quotient is 127
Yes. The quotient is 127.
1, 3, 5, 15, 25, 75, 127, 381, 635, 1905, 3175, 9525.
No, 381 is not a prime number. Other than itself and 1, it is divisible by 3 and 127.
A number that is divisible by both 456 and 381 is their least common multiple (LCM), which can be found by prime factorizing both numbers: 456 = 2^3 * 3 * 19 and 381 = 3 * 127. The LCM is therefore 2^3 * 3^2 * 19 * 127, or 1,456,404.
Some examples are... 381 474 726
No.
2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.
A number that is divisible by 15 is divisible both by 5 and 3 A number is divisible by 5 if it ends with 0 or 5 A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 4035 is divisible by 15 as it ends with a 5 and 4+0+3+5=12 which is divisible by 3
To check It is NOT an even number , so will not divide by '2' It does NOT end in '5' , so will not divide by '5'. The digits 381 do not sum to '9' ( 3+ 8 + 1= 12 = 3) So does not divide by '9'. 4. The clue is that the digits sum to '3' . Three is a prime number , so it might divide by '3'. If so, then it is a composite number. Hence 3)381 = 127 : No remainder. So 127 X 3 = 381 / Hence it is a composite number. NB When testing for composition of numbers, the other prime number to try is '7'.