No - 136/7 = 19.428571 recurring (that is, 19.428571428571...)
No.
Yes.
136
1, 2, 4, 8, 17, 34, 68, 136
No - 136/6 = 22.6 recurring (that is, 22.6666...)
136.
136
Because it is divisible by 2 leaving no remainder
Yes, 136 times.
Any element of the set of numbers of the form 136*k where k is an integer.
7 is not divisible by 104 and 104 is not divisible by 7.
Not only is 119 divisible by 7 but it is evenly divisible by 7.