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1 cubic foot =7.48 gallons. Your description is a little vague, though... assuming that it's 20 feet long and the shallow is is 10 feet long... 10 ft x 20 ft x 3 ft= 720 cubic feet which is 720 cu ft x 7.48 ga= 5386 gallons. That would leave the remaining amount of water at 35-12=23 So: 23 ft x 20 ft x 10 ft = 4600 x 7.48= 34408 Total water= 39794 gallons. However, that's assuming that it's a 90 degree drop from the 3 foot section to the 10 foot section. The slope will affect the amount of water in the pool. This should give you a rought estimate, though.

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Q: How many gallons of water are needed to fill a 20 foot long by 10 foot wide free form pool 3 x 10 feet on the shallow end and 6 x 10 feet on the deep end?

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Related questions

It can be shallow or deep.

25000 gallons

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