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Yes, if a generic square is made, and a toothpick along the vertical and horizontal line of symmetry, and then another generic square. 18 is enough to form it, and so is any double-digit number.

JK they cant share any. But maybe, if you use more than toothpicks

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Q: Is 18 toothpicks enough to form 5 quadrilaterals if no quadrilateral shares a toothpick with another quadrilateral?
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