No.
Nine is divisible by 1, 3 and 9.
No.
Three is a factor of nine.
35 remainder 3
No, to determine if a number is divisible by nine, add up the digits. If the sum is divisible by 9, then the number is divisible by 9. So 519 -> 5 + 1 + 9 = 15, which is not a multiple of nine. This 'trick' works on divisible by 9 and also divisible by 3, so 519 is divisible by 3, since 5 + 1 + 9 = 15, which is a multiple of 3. Yes. The result is a fraction though.
Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.
because the number three can go into the number nine.
No. For example, 9 is divisible by 3 and 9, but not 6. Even numbers that are divisble by 3 and 9 are also divisble by 6.
No. 3,569 is not evenly divisible by nine.
Nine is divisible by 1, 3, and 9.
No.First off, 120 is not divisible by 9. (The sum of the digits of 120 is "3"; a number is divisible by nine if and only if the sum of its digits is divisible by nine.) For that matter, it's not divisible by 36 either; since 36 is itself divisible by 9, any number which is not divisible by 9 cannot be divisible by 36.The smallest number that's divisible by 1, 2, 3, 6, 9, 12 and 36 is "36" (it's also divisible by 4, which you left out).
Sum the digits: 4+9=13 => NOT divisible by 3 Last digit is not 5 or 0 => NOT divisible by 5