Q: Is 2028 divisible by 3 and 8?

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Yes! 552 is divisible by 3 and 8

939 is evenly divisible by 3 939 is divisible by 8, but not evenly, quotient is 117, remainder is 3

1+4+3 = 8 which is not divisible by 3, so 143 is not divisible by 3. 8 ÷ 3 has remainder 2, so 143 ÷ 3 has remainder 2.

36 is divisible by itself but not 8 36/36=1 36/8=4.5

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0.002

Yes! 552 is divisible by 3 and 8

If the last 3 digits are divisible by 8, the number is divisible by 8.

939 is evenly divisible by 3 939 is divisible by 8, but not evenly, quotient is 117, remainder is 3

Sol: 24 = 3 x 8, where 3 and 8 are co-primes. The sum of the digits in the given number is 36, which is divisible by 3. So, the given number is divisible by 3. The number formed by the last 3 digits of the given number is 744, which is divisible by 8. So, the given number is divisible by 8. Thus, the given number is divisible by both 3 and 8, where 3 and 8 are co-primes. So, it is divisible by 3 x 8, i.e., 24.

888 because 8 is divisble by 2 and 8+8+8 is 24 24 is divisible by 3 then it is divisible by 2 and 3 then it is divisble by 6....

3*8*5=120, therefore 120 is divisible by 3, 8 and 5.

Becuz 8 mutiplied by 3 is 24

no because: 1+4+1+2=8 and 8 is not divisible by 3.

1+4+3 = 8 which is not divisible by 3, so 143 is not divisible by 3. 8 ÷ 3 has remainder 2, so 143 ÷ 3 has remainder 2.

24, and any multiple of 24 would be divisible by both 3 and 8.

36 is divisible by itself but not 8 36/36=1 36/8=4.5