3*8*5=120, therefore 120 is divisible by 3, 8 and 5.
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If the last 3 digits are divisible by 8, the number is divisible by 8.
There is no answer because for a number to be divisible by 8, it would end in an even number and therefore be divisible by 2.
For a number to be divisible by both 8 and 5 then : 1) the final digit must be zero (as a multiple of 5 ending in 5 is not divisible by 8) 2) As 1000 is divisible by 8 then only the last 3 digits of the number need to be checked to confirm if it is divisible by 8. 680 ÷ 8 = 85. Therefore the number has to be changed to 62680 to be divisible by both 8 and 5. Therefore, replace the digit 4 in 62684 with 0.
The divisibility rule of 3 is that you add the digits together and then if the number you come up with is divisible by 3, then the number itself is divisible by 3. In this instance, 5 + 8 + 5 = 18/3 = 6, therefore, 585 is divisible by 3.
The smallest number that is divisible by 2 3 4 5 6 7 8 9 and 10 is 2,520.