3*8*5=120, therefore 120 is divisible by 3, 8 and 5.
If the last 3 digits are divisible by 8, the number is divisible by 8.
There is no answer because for a number to be divisible by 8, it would end in an even number and therefore be divisible by 2.
For a number to be divisible by both 8 and 5 then : 1) the final digit must be zero (as a multiple of 5 ending in 5 is not divisible by 8) 2) As 1000 is divisible by 8 then only the last 3 digits of the number need to be checked to confirm if it is divisible by 8. 680 ÷ 8 = 85. Therefore the number has to be changed to 62680 to be divisible by both 8 and 5. Therefore, replace the digit 4 in 62684 with 0.
The divisibility rule of 3 is that you add the digits together and then if the number you come up with is divisible by 3, then the number itself is divisible by 3. In this instance, 5 + 8 + 5 = 18/3 = 6, therefore, 585 is divisible by 3.
The smallest number that is divisible by 2 3 4 5 6 7 8 9 and 10 is 2,520.
1200 = 3*5*8*10
Yes, it is true 558/3 = 186 To find out if a number is divisible by 3, add the digits; if the sum is divisible by 3, so is the number 5+5+8 = 18 which is divisible by 3
If sum of digits of a number is divisible by 3 then the number is divisible by 3. Sum of digits = 5+1+8 = 14 and 14 is not divisible by 3. So 518 is not divisible by 3.
Of 2, 3, 4, 5, and 8, the smallest number divisible by 2 is 2.
If the last 3 digits are divisible by 8, the number is divisible by 8.
1- Any number is divisible by 1. 2- Any even number is divisible by 2. 3- If its digits add up to a number divisible by 3, the whole number is divisible by 3. 4- If the last two digits are divisible by 4, the whole number is divisible by 4. 5- If it ends in 5 or 0, the whole number is divisible by 5. 6- If it's even and also divisible by 3, the whole number is divisible by 6. 7- There is no rule for 7. 8- If the last three digits are divisible by 8, the whole number is divisible by 8. 9- If its digits add up to a number divisible by 9, the whole number is divisible by 9. 10- If it ends in 0, the whole number is divisible by 10.
To determine if a number is divisible by 3, add all the digits. If the sum is divisible by 3, so is the number. 8+4+3+5 = 20, which is not divisible by 3 (not a multiple of 3). So, 8435 is not divisible by 3.
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To determine the smallest number that must be added to 403 to make it divisible by 8, first find the remainder when 403 is divided by 8. The remainder is 3 (since 403 ÷ 8 = 50 with a remainder of 3). To make it divisible by 8, you need to add 5 (8 - 3 = 5). Therefore, the smallest number to add is 5.
Sol: 24 = 3 x 8, where 3 and 8 are co-primes. The sum of the digits in the given number is 36, which is divisible by 3. So, the given number is divisible by 3. The number formed by the last 3 digits of the given number is 744, which is divisible by 8. So, the given number is divisible by 8. Thus, the given number is divisible by both 3 and 8, where 3 and 8 are co-primes. So, it is divisible by 3 x 8, i.e., 24.
There is no answer because for a number to be divisible by 8, it would end in an even number and therefore be divisible by 2.
For a number to be divisible by both 8 and 5 then : 1) the final digit must be zero (as a multiple of 5 ending in 5 is not divisible by 8) 2) As 1000 is divisible by 8 then only the last 3 digits of the number need to be checked to confirm if it is divisible by 8. 680 ÷ 8 = 85. Therefore the number has to be changed to 62680 to be divisible by both 8 and 5. Therefore, replace the digit 4 in 62684 with 0.