The last digit of 22 is '2' which is even (divisible by 2) so 22 is divisible by 2.
As a product of its prime factors: 2*3*7*13*13 = 7098
7098
The factors of 7098 are 1 2 3 6 7 13 14 21 26 39 42 78 91 169 182 273 338 507 546 1014 1183 2366 3549 7098.
No.
No
no
No.
No, it is not.
No... In order for a number to be divisible by 9, the sum of its digits must ALSO be divisible by 9. In this case, 7+0+9+6 = 22. 22 is not divisible by 9 !
Because 22 is divisible by numbers other than 1 and itself (22). 22 is divisible by 1, 2, 11 and 22 and hence it is composite number.
Out of that list, 22 is divisible by 2.