It is irrational.
YES.... squre root of 3 is in irrational number..
No, because the square root of 3 is an irrational number
Because 3 is a prime number and as such its square root is irrational
The square roots of 2 and 3 are irrational but not transcendent.
Surds are irrational numbers and 27 is a rational number but if you mean the square root of 27 then it is an irrational number and expressed as a surd it is 3 times square root of 3.
The square root of 3 is an irrational number
The square root of -3 is an imaginary number and the square root of 3 is an irrational number that can't be expressed as a fraction
It is irrational.
YES.... squre root of 3 is in irrational number..
No, because the square root of 3 is an irrational number
It is known that the square root of an integer is either an integer or irrational. If we square root2 root3 we get 6. The square root of 6 is irrational. Therefore, root2 root3 is irrational.
Because 3 is a prime number and as such its square root is irrational
The square roots of 2 and 3 are irrational but not transcendent.
Yes. For example, the square root of 3 (an irrational number) times the square root of 2(an irrational number) gets you the square root of 6(an irrational number)
Sometimes it is and sometimes it isn't. The square root of 2 and the square root of 3 are both irrational, as is their product, the square root of 6. The square root of 2 and the square root of 8 are both irrational, but their product, the square root of 16, is rational (in fact, it equals 4).
It is rational.The square root of 9 is 3 and it is a rational number