It is irrational.
YES.... squre root of 3 is in irrational number..
No, because the square root of 3 is an irrational number
Because 3 is a prime number and as such its square root is irrational
The square roots of 2 and 3 are irrational but not transcendent.
The square root of 3 is an irrational number
The square root of -3 is an imaginary number and the square root of 3 is an irrational number that can't be expressed as a fraction
It is irrational.
YES.... squre root of 3 is in irrational number..
Oh, dude, you're hitting me with some math lingo! So, like, 27 in surd form is √27. It's basically just the square root of 27, which simplifies to 3√3. But, like, who really needs all that fancy math talk, am I right?
No, because the square root of 3 is an irrational number
It is known that the square root of an integer is either an integer or irrational. If we square root2 root3 we get 6. The square root of 6 is irrational. Therefore, root2 root3 is irrational.
Because 3 is a prime number and as such its square root is irrational
The square roots of 2 and 3 are irrational but not transcendent.
Yes. For example, the square root of 3 (an irrational number) times the square root of 2(an irrational number) gets you the square root of 6(an irrational number)
Sometimes it is and sometimes it isn't. The square root of 2 and the square root of 3 are both irrational, as is their product, the square root of 6. The square root of 2 and the square root of 8 are both irrational, but their product, the square root of 16, is rational (in fact, it equals 4).
The square root of 9 is a rational number. This is because the square root of 9 is equal to 3, which can be expressed as a fraction, 3/1. In general, a rational number is any number that can be expressed as a ratio of two integers, which is the case for the square root of 9.