It depends on what you are calling "standard form". 2x = 7 can be solved, but it is a standard form of an algebraic equation.
9
Standard. You need a linear equation in two variables for slope-intercept form.
2x+12-3x = 5 2x-3x = 5-12 x = -7
What is the standard form for (2x+7)(x-1)=0
-5
3X^2 + 7 = 2X subtract 2X from each side and in standard form 3X^2 - 2X + 7 = 0 Use discriminant b^2 - 4ac (-2)^2 - 4(3)(7) = 4 - 84 < 1 so, no real roots
y=2x+7. The 2 is your slope and the 7 is your y intercept.
x2 - 10x - 6 = 2x + 1 Subtracting 2x + 1 from both sides gives: x2 - 12x - 7 = 0
Standard form is y = mx + b wher e m is slope and b is y intercept ayt x = 0 3 -2x = 5 -7y subtract 5 from both sides -2 -2x = - 7y divide both sides by -7 2/7 +2/7 x = y y = 2/7 x + 2/7
It is: 2x squared +5x -7 = 0 and the value of x = -7/2 or 1
If x=4 then 2x+7 =