No.
To check divisibility by 3 add the digits together and if the sum is divisible by 3, then so is the original number.
If the digits of the sum are summed and this is repeated until a single digit remains, then only if the digit is 3, 6 or 9 is the original number divisible by 3.
341 → 3 + 4 + 1 = 8 which is not divisible by 3 (not one of 3, 6 or 9), so 341 is not divisible by 3.
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