Q: Is 367 divisible by 3

Write your answer...

Submit

Related questions

no 360 = 120 x 3 so 363 366 369 are multiples not 367

No, 367 divided by 4 is 91.75

No.

No.

Since all numbers between 61 and 107 are less than 367, none of them are divisible by 367. 84 is a multiple of 3, 6 and 7 in that range.

1, 3, 9, 27, 367, 1101, 3303, 9909

No it is not. It is a prime number. Therefor it is only divisible by 1 and itself

367 is prime. It is only evenly divisible by itself and one.

122.3333

No - 367/3 = 122.3 recurring (that is, 122.3333...)

No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.

1, 2, 3, 5, 6, 10, 15, 30, 367, 734, 1101, 1835, 2202, 3670, 5505, 11010

It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.

3 is not divisible by 72. 72 is divisible by 3.

3 is not divisible by 630. 630 is divisible by 3.

No, it is not.

If x is an integer divisible by 3, is x squared divisible by 3?

A number is divisible by 3 if the sum of its digits is divisible by 3.

3 is not divisible by 126. 126 is divisible by 3.

No. 483 is not divisible by 6.A number is divisible by 6 if it is divisible by both 2 and 3.It is divisible by 2 if it is even and it is divisible by 3 if the sum of the digits is a multiple of 3.483 is not divisible by 6 since it is not divisible by 2 although it is divisible by 3.

1x6,743 not divisible by 2 no its not divisible by 3????

All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.

NO. 313 is not divisible by 3.A number is divisible by 3 if the sum of the digits is divisible by 3.313 = 3 + 1 + 3 = 7Note: 7 not divisible by 3 thus, 313 is not divisible by 3.

No, it is not evenly divisible by 3. The answer you get is 6,665.3333. A trick to tell is a number is divisible by 3 is to add up the digits and see if they are divisible by 3. In this case, 34 is not divisible by 3.

To be divisible by 6, the number must be divisible by both 2 and 3:To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8};To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3.As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3.If the number is not divisible by 2 or 3 (or both) then the number is not divisible by 6.examples:126Last digit is even so it is divisible by 2 1 + 2 + 6 = 9 which is divisible by 3, so it is divisible by 3â†’ 126 is divisible by both 2 and 3, so it is divisible by 6124Last digit is even so it is divisible by 2 1 + 2 + 4 = 7 which is not divisible by 3, so it is not divisible by 3â†’ 126 is divisible by 2 but not divisible by 3, so it is not divisible by 6123Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 3 = 6 which is divisible by 3, so it is divisible by 3â†’ 123 is divisible by 3 but not divisible by 2, so it is not divisible by 6121Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 1 = 4 which is not divisible by 3, so it is not divisible by 3â†’ 121 is not divisible by either 2 or 3, so it is not divisible by 6