36 is divisible by itself but not 8 36/36=1 36/8=4.5
Always. A number divisible by another is also divisible by all the factors of that number. A number that is divisible by 10 is also divisible by 2 and 5. Take any multiple of 10 and check it. 70/5=14 or 180/5=36
To be divisible by 36 the number must be divisible by 9 (and 4). To be divisible by 9, the sum of the digits must be divisible by 9. 5 + 5 = 10 → need an extra 8 → A + B = 8.
No.First off, 120 is not divisible by 9. (The sum of the digits of 120 is "3"; a number is divisible by nine if and only if the sum of its digits is divisible by nine.) For that matter, it's not divisible by 36 either; since 36 is itself divisible by 9, any number which is not divisible by 9 cannot be divisible by 36.The smallest number that's divisible by 1, 2, 3, 6, 9, 12 and 36 is "36" (it's also divisible by 4, which you left out).
No. 29 is a prime number; 36 is not divisible by 29.No. 29 is a prime number; 36 is not divisible by 29.No. 29 is a prime number; 36 is not divisible by 29.No. 29 is a prime number; 36 is not divisible by 29.
36 and all multiples of 36 all multiples of 36 that do not end in 0 (72, 108, 144, etc.)
36 = 1, 2, 3, 4, 6, 9, 12, 18 & 36 * * * * * Wrong. These are number that divide 36 not numbers that are divisible by 36! Numbers that are divisible by 36 are the numbers in the 36 times table: 36, 72 , 108, 144, 180 etc.
The multiples of 36 (which are infinite) are all divisible by 36, including these: 36, 72, 108, 144, 180, 216, 252, 288 . . .
A number divisible by both 2 and 5 will be divisible by their product (2 x 5), which is 10. Any number divisible by 10 ends in 0. The only number listed that ends in 0 is 110.
2970/36 = 82.5
36, 72,108,144 ------------------- 4x9=36, now multiples of 36 will always be divisible by 4 and 9
36 = 10*9*4 The last digit must be 0. The digital root (sum of digits) must be divisible by 9. By the first requirement, above, the number must be divisible by 10. The quotient, after division by 10, must be divisible by 4.