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How do you write a program that prints out the first 100 prime numbers using OOP?
You do not need OOP for this because the first 100 prime numbers are all integral types. All you need is a function to determine if a given integral is prime or not, and another to find the next prime after a given integral: bool is_prime (const unsigned int num) { unsigned factor, max_factor; /* anything less than 2 is non-prime */ if (num<2) return false; /* 2 is the only even prime */ if (!(num%2) return num==2; /* determine largest potential factor of num (square root of num)*/ max_factor = sqrt (num); /* test each odd factor from 3 onwards */ for (factor=3; factor<=max_factor; factor+=2) { if (!(num%factor)) return false; /* num is non-prime */ } return true; /* the number is prime */ } unsigned next_prime (unsigned int num) { /* increment num until num is prime */ while (!is_prime (++num)); return num; } /* test the functions */ int main (void) { unsigned num, count; count=0; num=0; printf ("Printing the first 100 prime numbers:\n"); while (count<100) { num=next_prime (num); printf ("%d is prime\n", num); ++count; } return 0; }
Write a unix shell program to print the prime numbers?
i=2 rem=1 echo "Enter a number" read num if [ $num -lt 2 ] then echo "$num is not prime" exit 0 fi while [ $i -le `expr $num / 2` -a $rem -ne 0 ] do rem=`expr $num % $i` i=`expr $i + 1` done if [ $rem -ne 0 ] then echo "$num is prime" else echo "$num is not prime" fi
How do you write a C program to check whether a number is prime or not and to find the nth prime number?
int number; int i=2; while (i<number) { if(number%i==0) { printf("Not a prime no."); break; } else printf("number entered is prime"); getch(); }
How do you write a C program to generate the first 50 prime numbers?
/*Determine prime numbers between 1 to 50*/ #include<stdio.h> #include<conio.h> main() { int num, i ,n; clrscr(); printf ( "\nEnter a number limit" ) ; scanf ( "%d", &n ) ; for ( num=2; num <= 50; num++ ) { for ( i=2; i <= num - 1; i++ ) { if ( num % i == 0 ) { Break; continue; } } if (num==i) printf(\n The prime number=%d", num); continue; } getch() }
Is 73 a prime num?
Yes, 73 is a prime number.
Shell script to find a prime no?
i=2 rem=1 echo -e "Enter a number: \c" read num if [ $num -lt 2 ]; then echo -e "$num is not prime\n" exit 0 fi while [ $i -le `expr $num / 2` -a $rem -ne 0 ]; do rem=`expr $num % $i` i=`expr $i + 1` done if [ $rem -ne 0 ]; then echo -e "$num is prime\n" else echo -e "$num is not prime\n" fi
Write a program that computes and prints X-th prime number where X equals 125 plus 20?
#include#includebool is_prime(unsigned num) {unsigned max, factor;if (num
How do you write a c program to find prime numbers between 1 to 10000 using functions?
You need two utility functions. The first determines if a given number is prime or not. The second finds the next prime after a given number. The following function can be used to determine if a given integer is prime: bool is_prime (const unsigned num) { if (num<2) return false; if (0==(num%2)) return num==2; unsigned max_factor = (unsigned) sqrt ((double) num) + 1; unsigned factor; for (factor=3; factor<max_factor; ++factor) if (0==(num%factor)) return false; return true; } The following function can be used to determine the next prime after the given integer: unsigned next_prime (unsigned num) { while (!is_prime (++num)); return num; } Now you can print a series of primes using the following: int main (void) { unsigned num=1; while (num<10000) { num = next_prime (num); printf ("%d is prime\n", num); } return 0; }
Is 5 a prime num ber?
YES 5 is a prime number!
How do you write a program in lisp to find if a number is prime or not?
(defun prime (num) (if (< 2 num) (do ((dividend 2 (1 + dividend)) (chk-to (sqrt num))) ((equal (rem num dividend) 0)) (when (<= chk-to dividend) (return t))) t))
Write a c program to accept the range of all prime numbers from 1 to n by using while loop?
#include<iosys.h> #include<math.h> // for sqrt() bool is_prime (unsigned num) { if (num<2) return false; // 2 is the first prime if (!(num%2)) return num==2; // 2 is the only even prime // largest potential factor is square root of num unsigned max = (unsigned) sqrt ((double) num) + 1; // test all odd factors for (unsigned factor=3; factor<max; factor+=2) if (!(num%factor)) return false; return true; // if we get this far, num has no factors and is therefore prime } int main (void) { // test all nums from 0 to 100 inclusive for (unsigned num=0; num<=100; ++num) { if (is_prime (num)) printf ("%d is prime\n", num); else if (num>0) printf ("%d is composite\n", num); else printf ("%d is neither prime nor composite\n", %d); } return 0; }
Program to find the first prime numbers to 1000?
#include<iostream> // std::cout and std::endl #include<cmath> // std::sqrt // returns the next prime number after the given numberunsigned next_prime (unsigned num) { if (num<2) return 2; ++num; unsigned max_factor {std::sqrt{num) + 1U}; for (unsigned factor=2; factor<max_factor; ++factor) if (num%factor==0) return next_prime (num); return num; } // print prime numbers to 1000 int main() { unsigned num=0; while ((num=next_prime(num))<1000) std::cout<<num<<std::endl; }
