0
No.
39 is odd but 6 is even and all multiples of 6 are even.
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
What is 78 divisible by?
2, 3, 6, and 39
Is 39 divisible by 2 3 5 6 or 10?
Yes.
Is 39 divisible by 2?
No, it is divisible by 1, 3, 13, 39.
Is 39 divisible by3?
39 is divisible by 3. It equals 13. You can tell if a number is divisible by 3 by adding up the digits in the number and see if it is divisible by three. Here's and example: 197 1+9+7= 17 and 17 isn't divisible by three. 576 5+7+6= 18 and 3 goes into 18 6 times so it is divisible by 3
What are the divisible numbers for 234?
234 is divisible by: 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117 and 234.
What is 78 divisible by?
2, 3, 6, and 39
Is 39 divisible by 2 3 5 6 or 10?
Yes.
Is 39 divisible by 2?
No, it is divisible by 1, 3, 13, 39.
Is 39 divisible by3?
39 is divisible by 3. It equals 13. You can tell if a number is divisible by 3 by adding up the digits in the number and see if it is divisible by three. Here's and example: 197 1+9+7= 17 and 17 isn't divisible by three. 576 5+7+6= 18 and 3 goes into 18 6 times so it is divisible by 3
Can 117 over 54 be simplified?
Yes, both are divisible by 3, = 39/18, both are also divisible by 9, = 13/6
What numbers are seventy eight divisible by?
1, 2, 3, 6, 13, 26, 39, 78
What are the divisible numbers for 234?
234 is divisible by: 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117 and 234.
What is the number nearest to 39 that is exactly by divisible 4?
40 is nearest to 39 and is exactly by divisible 4
Is 39 divisible by 4?
No - 39/4 = 9.75
Why is 39 a composite number?
Because it is divisible by numbers other than 1 and itself. 39 is divisible by 1, 3, 13, 39.
Is 39 a prime or composite Explain how you know?
composite 3 goes into 3 or 30 3 goes into 9 so 3 goes into 39 13 + 13 + 13 = 39 = 3 x 13 ------------------------------------- Applying a divisibility test: To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3. As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3. For 39 this gives: 39 → 3 + 9 = 12 12 → 1 + 2 = 3 3 is one of {3, 6,9} so 39 is divisible by 3. As 39 is divisible by 3 (that is 3 is a factor of 39 that is less than 39) and 3 is greater than 1 then 39 is a composite number.
Is 39 divisible 2?
No.
