2, 3, 6, and 39
Yes.
No, it is divisible by 1, 3, 13, 39.
39 is divisible by 3. It equals 13. You can tell if a number is divisible by 3 by adding up the digits in the number and see if it is divisible by three. Here's and example: 197 1+9+7= 17 and 17 isn't divisible by three. 576 5+7+6= 18 and 3 goes into 18 6 times so it is divisible by 3
234 is divisible by: 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117 and 234.
2, 3, 6, and 39
Yes.
No, it is divisible by 1, 3, 13, 39.
39 is divisible by 3. It equals 13. You can tell if a number is divisible by 3 by adding up the digits in the number and see if it is divisible by three. Here's and example: 197 1+9+7= 17 and 17 isn't divisible by three. 576 5+7+6= 18 and 3 goes into 18 6 times so it is divisible by 3
Yes, both are divisible by 3, = 39/18, both are also divisible by 9, = 13/6
1, 2, 3, 6, 13, 26, 39, 78
234 is divisible by: 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117 and 234.
40 is nearest to 39 and is exactly by divisible 4
No - 39/4 = 9.75
Because it is divisible by numbers other than 1 and itself. 39 is divisible by 1, 3, 13, 39.
composite 3 goes into 3 or 30 3 goes into 9 so 3 goes into 39 13 + 13 + 13 = 39 = 3 x 13 ------------------------------------- Applying a divisibility test: To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3. As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3. For 39 this gives: 39 → 3 + 9 = 12 12 → 1 + 2 = 3 3 is one of {3, 6,9} so 39 is divisible by 3. As 39 is divisible by 3 (that is 3 is a factor of 39 that is less than 39) and 3 is greater than 1 then 39 is a composite number.
No.