1, 3, 5, 7, 9, 15, 21, 35, 45, 63, 105, 139, 315, 417, 695, 973, 1251, 2085, 2919, 4865, 6255, 8757, 14595, 43785.
Almost the same rule and dividing by 3. Add up all the digits in the number. Find out what the sum is. If the sum is divisible by 9, so is the number.For example: 43785 (4+3+7+8+5=27) 27 is divisible by 9, therefore 43785 is too!
1, 3, 5, 7, 9, 15, 21, 35, 45, 63, 105, 139, 315, 417, 695, 973, 1251, 2085, 2919, 4865, 6255, 8757, 14595, 43785 3, 5, 7 and 139 are prime.
Factors: 1, 3, 5, 7, 9, 15, 21, 35, 45, 63, 105, 139, 315, 417, 695, 973, 1251, 2085, 2919, 4865, 6255, 8757, 14595, 43785.Prime factors: 3 x 3 x 5 x 7 x 139
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
YES. 285 is divisible by 5. A number is divisible by 5 if it ends with 0 or 5
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
Yes, 1255 is divisible by 5, and any number that ends in 5 is divisible by 5.
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.
No, because 1 is not evenly divisible by 5. However, all numbers divisible by 5 are divisible by 1.
5/5715 = 0.000874891 5 is not evenly divisible by 5715. However, 5715 is divisible by 5. (If a number ends in 5 or 0 it is divisible by 5.) 5715/5 = 1143
5 is not divisible by 1260. 1260 is divisible by 5 because 1260 is a multiple of 5.