No. 483 is not divisible by 6.A number is divisible by 6 if it is divisible by both 2 and 3.It is divisible by 2 if it is even and it is divisible by 3 if the sum of the digits is a multiple of 3.483 is not divisible by 6 since it is not divisible by 2 although it is divisible by 3.
It is composite because it is divisible by 3(4 + 8 + 3 = 15)
no. anything divisible by 5 ends in a 5 or 0.
11,109 is divisible by these factors: 1, 3, 7, 21, 23, 69, 161, 483, 529, 1587, 3703, 11109.
161, 322, 483, 644, and all other multiples of 161 are divisible by 161.
No. 483 is not divisible by 6.A number is divisible by 6 if it is divisible by both 2 and 3.It is divisible by 2 if it is even and it is divisible by 3 if the sum of the digits is a multiple of 3.483 is not divisible by 6 since it is not divisible by 2 although it is divisible by 3.
no, it is divisible by 3
No.
It is composite because it is divisible by 3(4 + 8 + 3 = 15)
483 / 9 is equal to 53.67 or 53 with remainder 6.
no. anything divisible by 5 ends in a 5 or 0.
11,109 is divisible by these factors: 1, 3, 7, 21, 23, 69, 161, 483, 529, 1587, 3703, 11109.
Not evenly as it gives you 241.5
Yes 966 / 2 = 483
15, and every number that is a multiple of 15: 15, 30, 45, 60, ...
161, 322, 483, 644, and all other multiples of 161 are divisible by 161.
1, 3, 7, 11, 21, 23, 33, 69, 77, 161, 231, 253, 483, 759, 1771, 5313.