Yes.
No. 483 is not divisible by 6.A number is divisible by 6 if it is divisible by both 2 and 3.It is divisible by 2 if it is even and it is divisible by 3 if the sum of the digits is a multiple of 3.483 is not divisible by 6 since it is not divisible by 2 although it is divisible by 3.
It is composite because it is divisible by 3(4 + 8 + 3 = 15)
11,109 is divisible by these factors: 1, 3, 7, 21, 23, 69, 161, 483, 529, 1587, 3703, 11109.
no. anything divisible by 5 ends in a 5 or 0.
161, 322, 483, 644, and all other multiples of 161 are divisible by 161.
No. 483 is not divisible by 6.A number is divisible by 6 if it is divisible by both 2 and 3.It is divisible by 2 if it is even and it is divisible by 3 if the sum of the digits is a multiple of 3.483 is not divisible by 6 since it is not divisible by 2 although it is divisible by 3.
no, it is divisible by 3
To determine if 483 is divisible by 9, we can add the digits of 483 together: 4+8+3 = 15. Since 15 is not divisible by 9 (15 ÷ 9 = 1 with a remainder of 6), we can conclude that 483 is not divisible by 9. In general, a number is divisible by 9 if the sum of its digits is divisible by 9.
No.
It is composite because it is divisible by 3(4 + 8 + 3 = 15)
11,109 is divisible by these factors: 1, 3, 7, 21, 23, 69, 161, 483, 529, 1587, 3703, 11109.
no. anything divisible by 5 ends in a 5 or 0.
Not evenly as it gives you 241.5
Yes 966 / 2 = 483
161, 322, 483, 644, and all other multiples of 161 are divisible by 161.
1, 3, 7, 11, 21, 23, 33, 69, 77, 161, 231, 253, 483, 759, 1771, 5313.
To find two numbers that multiply to 483, we need to factorize 483. The prime factorization of 483 is 3 x 7 x 23. Therefore, the two numbers that multiply to 483 are 3 and 161, as 3 x 161 = 483.