No it's not.
You can try it yourself by using a calculator and seeing if those numbers fit into 48.
48 is divisible by: 1 2 3 4 6 8 12 16 24 48.
No, 48 is not prime. It is divisible by numbers other than 1 and itself. For example, it can be evenly divided by 2, 3, 4, 6, 8, 12, 16, and 24.
The integral factors of 48 are 48, 24, 16, 12, 8, 6, 4, 3, 2, and 1. Of these, 48, 24, 12, 6, and 3 are integrally divisible by 3, for a total of 5.
Prime numbers are only divisible by 1 and themselves. So, a prime number cannot be divisible by 10. The only prime number that is divisible by 2 is 2 itself; all other numbers divisible by 2 are not prime numbers.
No, it is not.
Factors of 48 that are between 1 and 10:1, 2, 3, 4, 6, and 8.
48 is divisible by: 1 2 3 4 6 8 12 16 24 48.
9
24:48. 1:2. 48 and 24 is divisible by 2 and 1 respectively. The ratio is 1:2
10 is divisible by 1, 2, 5 & 10
LOL, have you even been listening to your math teacher? Any number with a last digit that isn't zero isn't divisible by 10. The answer is no.
The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48The factors of 76 are: 1, 2, 4, 19, 38, 76
1, 2, 3, 4, 6, 8, 12, 16, 24, 48
48/2 = 24 48/3 = 16 48/4 = 12 48/6 = 8 48/8 = 6 48/12 = 4 48/16 = 3 48/24 = 2
48 is divisible by 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.
By: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
No, 48 is not prime. It is divisible by numbers other than 1 and itself. For example, it can be evenly divided by 2, 3, 4, 6, 8, 12, 16, and 24.