Any element of the set 492*k where k is an integer.
No.
Yes.
yes 984 is divisible by two it equals 492
Yes, the result is 164.
No, 492 is only divisible by 1, 2, 3, 4, 6, 12, 41, 82, 123, 164, 246, 492.
492 is an even number so it must be divisible by 2. Its digits total a multiple of 3 so it must be divisible by 3. Any even number that is divisible by 3 is divisible by 6. Of course, you can always divide 492 by 6. If it comes out even, it's a factor. (It does.)
Yes it is. 2 is a factor because 492 ends in 2, 3 is a factor because 4+9+2 is divisible by 3. So 6 is a factor.
As an even number greater than 2, 492 is divisible by 2 and therefore composite. Its positive integer factors are: 1, 2, 3, 4, 6, 12, 41, 82, 123, 164, 246, 492
By the multiples of 123 (which are infinite), including these: 123, 246, 369, 492, 615, 738, 861, 984, 1107 . . .
28% of 492= 28% * 492= 0.28 * 492= 137.76
ANSWER: 49200%492= 492 * 100%= 49200%