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Q: Is 4x2 9 prime

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4x2 = 8, 8-9 = -1 therefore the answer is "-1"

4x2 - 36x + 81 = 4x2 - 18x - 18x +81 = 2x(2x - 9) - 9(2x - 9) = (2x - 9)2

4x2-36x+81 (2x-9)(2x-9)

4x2 - 3x - 9

No, it has factors... 4x2 + 8x -21 = (2x+7)(2x-3)

no it isn't because 4x2 =8.

NUMBERS! no 3 is prime, 7 also prime and 8 is 4x2

Not if x is an integer.

The expression is likely 4x2 - 36x +81 which is the same as (2x - 9)(2x - 9) or (2x - 9)2

4x2 =8 1x8 =8 1x9=9

first it is 80x7- 7 is prime then, ^ 8x10- then ^ ^ 4x2 and 5x2- 5,2,2 are prime...then, ^ 2x2 then your done !

Only if the value of c is 9 because:- 4x2+12x+9 = (2x+3)(2x+3)

4x2+49x+90 = (4x+9)(x+10) when factored

2 is a prime number so it has no prime factorization 8 is 4X2 and 2X2 is 4 so the factorization of 8 is 2X2X2

4x2 - 12x + 9 = 5; whence, 2x - 3 = ±√5, and 2x = 3 ±√5. Therefore, x = ½ (3 ±√5).

3x3=9 So, it could only be 9x1 which=9. 3x1=3 3 does not equal 9. 4x2=8 8 does not equal 9. 6x3=18 18 does not equal 9

4x2 - 9 = (2x + 3)(2x - 3)

(2x - 9)(2x - 9)

(2x - 9)(2x +9)

Simple...4x2-9=04x2=9x2=9/4x=+3/2 or -3/2Missed a step. :)x2=9/4x2=3/2x= square root of +- 3/2

9 is not prime.

(2x - 3)(2x + 3)(4x2 + 9)

(2x - 7)(2x - 9)

y = 2 (4X2=8) +9 = 17

4x2 - 12x + 9 = 4x2 - 6x - 6x + 9 = 2x(2x - 3) - 3(2x - 3) = (2x - 3)(2x - 3) or (2x - 3)2