There are (500-100)/2 = 200 numbers divisible by 2 between 100 and 500 counting 100 but not 500. Of these (500-100)/8 = 50 are divisible by 8. So there are 150 numbers between 100 and 500 divisible by two but not by 8. By relative primeness exactly 50 out of these 150 are divisible by 3 and therefore these 50 are exactly the ones divisible by 6 but not by 8.
There are 67 numbers between 100 and 500 divisible by 6. The first number greater than 100 divisible by 6: 100 ÷ 6 = 16 r 4 → first number divisible by 6 is 6 × 17 = 102 Last number less than 500 divisible by 6: 500 ÷ 6 = 83 r 2 → last number divisible by 6 is 6 × 83 = 498 → all multiples of 6 between 17 × 6 and 83 × 6 inclusive are the numbers between 100 and 500 that are divisible by 6. → there are 83 - 17 + 1 = 67 such numbers.
251
1, 2, 4, 5, 10, 20, 25, 50, 100, 125, 250, 500
No. 500 is not evenly divisible by nine.
Each and every number that is multiple of 5 is also divisible by 5 e.g. 5*1 = 5 5*2 = 10 5*5 = 25 5*100 = 500 5, 10 , 25 and 500 are multiples of 5, so all these numbers are also divisible by 5 e.g. 500/5 = 100
1, 2, 4, 5, 10, 20, 25, 50, 100, 125, 250, 500.
No:2,500 is divisible by 1, 2, 4, 5, 10, 20, 25, 50, 100, 125, 250, 500, 625, 1250, 2500.
Just 1.
No, it is not.
There are many numbers between 500 and 1000 divisible by 3 and 9. Any number divisible by 9 is divisible by 3. How about 900?
102 105 108 111 114 117 120 498