525 is divisible by 5, since it ends with a 5. 525/5 = 105 525 is not divisible by 2, since it does not end with 0, 2, 4, 6, or 8. 525/2 = 262.5
All multiples of 525 (which are infinite) including 525, 1050, 1575, 2100, 2625 . . .
Yes, evenly
510
The list is infinite. Here are some of them: 210, 315, 420, 525, 630, 735, 840.
1, 3, 5, 7, 15, 21, 25, 35, 75, 105, 175, 525
525 is divisible by 5, since it ends with a 5. 525/5 = 105 525 is not divisible by 2, since it does not end with 0, 2, 4, 6, or 8. 525/2 = 262.5
All multiples of 525 (which are infinite) including 525, 1050, 1575, 2100, 2625 . . .
Yes, evenly
525 = 35 x 15
510
Yes.
There are eight pairs of numbers divisible by three that sum to 150, and 75 is also divisible by three, so: sum = 17 * 75 = 750 + 525 = 1275
No. To find out if a number is divisible by 3, just add up the numbers and if that number is divisible by three then the whole number is. So, 5+3+5=13, so it is not divisible by three. 5+2+5=12, so 525 IS divisible by three. Pretty neat, huh?!
First determine which of the numbers are divisible by 5.They are:70430525Then you find the sum of these. 70+430=500. 500+525=1025.
The list is infinite. Here are some of them: 210, 315, 420, 525, 630, 735, 840.
510. To be divisible by 3, it must be a multiple of 3. Thus the required number is a multiple of both 3 and 5, which will be a multiple of their lcm: lcm(3, 5) = 15. → 495 ÷ 15 = 33 → first multiple of 15 greater than 495 is 15 x 34 = 510 → 525 ÷ 15 = 35 → last multiple of 5 less than 525 is 15 x 34 x 510 → number required is 510.