Step 1: Use the divisibility rule for 13
One method:
Take the last digit, multiply it by 9.
Subtract that from the rest of the number.
If the result is divisible by 13, the original number is divisible by 13.
Step 2: Apply the rule
Number: 83,525
Last digit = 5 →
5
×
9
=
45
5×9=45
Rest of the number = 8,352
Subtract:
8
,
352
−
45
=
8
,
307
8,352−45=8,307
Step 3: Repeat the process
Last digit = 7 →
7
×
9
=
63
7×9=63
Rest of the number = 830
Subtract:
830
−
63
=
767
830−63=767
Step 4: Repeat again
Last digit = 7 →
7
×
9
=
63
7×9=63
Rest = 76
Subtract:
76
−
63
=
13
76−63=13
Step 5: Check goto.now/YJkWW 👈🏻
525 is divisible by 5, since it ends with a 5. 525/5 = 105 525 is not divisible by 2, since it does not end with 0, 2, 4, 6, or 8. 525/2 = 262.5
Oh, isn't that a happy little question! To find a number divisible by 525, we can start by looking for numbers that are multiples of both 5 and 105 (which is 525 divided by 5). So, any number that is a multiple of 525, like 525, 1050, 1575, and so on, will be divisible by 525. Keep on exploring and you'll find the perfect number that fits just right!
Yes, evenly
No, 83 is not divisible by 3. When a number is divisible by another number, it means that the division will result in a whole number without a remainder. In this case, when you divide 83 by 3, you get 27 with a remainder of 2, which means 83 is not divisible by 3.
525 = 35 x 15
166 is divisible by: 2, 83.
Yes, the result is 175.
No
No.
83 is a prime number because it is only divisible by 1 and itself (83) if would be composite if it were divisible by any other number.
83 is a prime number because it is only divisible by 1 and itself (83) if would be composite if it were divisible by any other number.
Not evenly because 83/4 = 20.75