No three, four, five, six, nine, and ten don't go in it.
56 is divisible by: 1, 2, 4, 7, 8, 14, 28, 56.
56 of them.
The numbers that are divisible by 28 are infinite. The first four are: 28, 56, 84, 112 . . .
1x56 2x56 3x56 etc.
All number that are completely divisible by 10 (with no remainder) end in 0 (zero). Dividing 565 by 10 yields 56 with a remainder of 5 (or 56.5 or 56½) - so - NO - 565 is NOT divisible by 10.
56 is divisible by: 1, 2, 4, 7, 8, 14, 28, 56.
56 of them.
The numbers that are divisible by 56 are in the form 56k where k is the integer constant.
The numbers that are divisible by 28 are infinite. The first four are: 28, 56, 84, 112 . . .
8, 7, 2, 28
1x56 2x56 3x56 etc.
All number that are completely divisible by 10 (with no remainder) end in 0 (zero). Dividing 565 by 10 yields 56 with a remainder of 5 (or 56.5 or 56½) - so - NO - 565 is NOT divisible by 10.
Nope - it's not divisible by 3,5,6, 9 or 10 The factors of 56 are:- 1,2,4,7,8,14,28,56
There are 10 numbers between 10 and 80 that are divisible by 7 with no remainder: 14, 21, 28, 35, 42, 49, 56, 63, 70, and 77.
224 is evenly divisible by these numbers: 1, 2, 4, 7, 8, 14, 16, 28, 32, 56, 112 and 224.
Two is divisible by 56, but the number does not come out evenly. You get 0.0357 as your answer. 56 is divisible by 2 and it goes in evenly, however. (56/2 is 28).
No number between 20 and 40 is divisible by all 4 numbers. The smallest number divisible by all 4 of those numbers is: 56