No. A variable must not start with a number. B5, however, would be acceptable.
a variable minus a number and the same variable is b-6b= -5b
10
5b + 5b = 2 x 5b
The GCF is 5b.
2a+5b isn't possible the answer is still 2a+5b.
5b-15 = -10
5b-32
5b
15 = 5b
3a + (3b - 2a) + 5b =3a + 3b - 2a + 5b =(3a - 2a) + (3b + 5b) =a + 8b
5b+6=32-8bSince -8b contains the variable to solve for, move it to the left-hand side of the equation by adding 8b to both sides.5b+6+8b=32Since 5b and 8b are like terms, add 8b to 5b to get 13b.13b+6=32Since 6 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 6 from both sides.13b=-6+32Add 32 to -6 to get 26.13b=26Divide each term in the equation by 13.(13b)/(13)=(26)/(13)Simplify the left-hand side of the equation by canceling the common terms.b=(26)/(13)Simplify the right-hand side of the equation by simplifying each term.b=2
5b + 3 = 10 - 3 - 3 5b = 7 5b/5 7/5 b= 1.5 There you go !