No, to be an even number the number has to be "0" or be divisible by the number 2 with no remainder. 5/2=2.5
5+5+5+5+1 That is only 5 numbers being added. There can be no answer for six numbers for the following reasons: The numbers are all odd. Two odd numbers make an even number. Two even numbers make an even number. 21 is odd. Take 6 odd numbers and add them up in pairs. Each pair of odd numbers gives an even number so there are 3 even numbers. Even + Even + Even = Even. So sum of any six odd numbers is even but 21 is not even.
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No. Those two numbers are odd numbers. Even numbers can be divided in half evenly.
10 can be divided by 5. 10 is even. 15 can be divided by 5. 15 is odd. So some of the numbers that can be divided by 5 are odd and some are even.
Multiples of 5 in even numbers occur when an even number is divisible by 5. Since even numbers are integers that are divisible by 2, a multiple of 5 in an even number would be a number that is divisible by both 2 and 5. This means the number must be a multiple of 10, as 10 is the least common multiple of 2 and 5. Examples of such numbers include 10, 20, 30, and so on.
Even numbers are numbers that are evenly divisible by 2. The first five even numbers would be 2, 4, 6, 8, and 10.
Even numbers have to end with 2, 4, 6, 8, or 0. And multiples of 5 have to end in 5 or 0.
There are four even numbers between one and nine. the four even numbers are 2,4,6 and 8.
This is not always true. If the sum of two numbers is even, then those two numbers are either both even or both odd. For example: 2 + 2 = 4 (even + even = even) 5 + 7 = 12 (odd + odd = even) 3 + 2 = 5 (odd + even = odd)
With a total of 90,000 five digit numbers, we can conclude that there is 45,000 EVEN five digit numbers.
If the sum of two numbers is even, the two numbers are either both even or both odd. A few examples:2 + 4 = 6 (even + even = even)2 + 3 = 5 (even + odd = odd)5 + 2 = 7 (odd + even = odd)7+13 = 20 (odd + odd = even)
There are 5 even numbers from 1 to 10: 2, 4, 6, 8, and 10. An even number is an integer that is divisible by 2 without leaving a remainder. In this case, all of the even numbers between 1 and 10 fit this criteria.