No.
If the last digit of a number is 0, 2, 4, 6, 8 or 0 then the number is divisible by 2. The digit of 619 is 9, so 619 is not divisible by 2.
Any one of the infinite set of numbers of the form 619*k where k is an integer.
123.8
Yes, it equals 619. Any number ending in 0, 2, 4, 6, or 8 is divisible by 2.
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
123.8
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
Yes, 1255 is divisible by 5, and any number that ends in 5 is divisible by 5.
YES. 285 is divisible by 5. A number is divisible by 5 if it ends with 0 or 5
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.
No, because 1 is not evenly divisible by 5. However, all numbers divisible by 5 are divisible by 1.
5/5715 = 0.000874891 5 is not evenly divisible by 5715. However, 5715 is divisible by 5. (If a number ends in 5 or 0 it is divisible by 5.) 5715/5 = 1143