No.
Only numbers ending in 0 or 5 are divisible by 5.
It is divisible by 1, 2, 4, 5, 10, 17, 20, 34, 68, 85, 170, and 340.
3,468
Yes 68 times
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
Yes, 1255 is divisible by 5, and any number that ends in 5 is divisible by 5.
68 is divisible by 17 but not by 3.
It is divisible by 1, 2, 4, 5, 10, 17, 20, 34, 68, 85, 170, and 340.
The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60 The factors of 68 are: 1, 2, 4, 17, 34, 68
Well, like any other real number, 68 is divisible by any number except for 0, as division by zero is undefined. 68 is evenly divisible (with no remainder) by: 1; 2; 4; 17; 34; 68 [hope I did not miss any]
no
2,4,1,68
Since 10 is smaller, let's look at it's factors first: 10 = 2*5 Because 68 doesn't end in either a 5 or a 0, we know it isn't divisible by 5. Since it is even, it is divisible by 2. Thus their GCF is 2.
No. 68 is not evenly divisible by 15.
No because 68/13 is 5.23076923
68. 68 is divisible by 17.
3,468
Any number of the form 68*k where k is an integer.